Solitaire 1.2ct Princess CZ Pendant Necklace in Sterling Silver
Solitaire 1.2ct Princess CZ Pendant Necklace in Sterling Silver
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Description
- Metal: Sterling silver, rhodium plated, stamped 925, nickel free.
- Stone: Set with premium quality 1.2 carat (6mm) princess cubic zirconia in 4-prong setting.
- Measurement: Chain measures 18" in length. Pendant measures 0.45" (L), 0.28" (W). Lobster claw clasp.
- Style No: N1541-01
This solitaire pendant necklace will effortlessly illuminate any outfit with its classic cut and undeniable radiance.
The perfect combination of shine, sweetness and style, a princess cut style is ideal for someone girly and lively.
Product Details & Materials
Product Details & Materials
Jewelry Information
| Style Number | N1541-01 |
|---|---|
| Metal | 925 sterling silver |
| Plating | rhodium plated |
| Finish | polished |
| Nickel Free | Yes |
| Measurements | 0.45 inch in length; 0.28 inch in width; |
| Chain Type | rolo |
| Chain Length | 18 inch |
| Chain Width | 1mm |
| Clasp | lobster claw clasp |
| Jewelry Weight | 3.4 Grams |
cubic zirconia Information
| Stone Cut | princess cut |
|---|---|
| Stone Size | 6mm |
| Stone Color | clear Color |
| Stone Setting | 4-prong |
| Stone Quantity | 1 Stone |
| Stone Weight | 1.2 ct.tw |
* All cubic zirconia stone weights are approximate and listed as diamond equivalent weight in carats.
Jewelry Care Tips
Jewelry Care Tips
Caring for your jewelry will ensure that it will last for years to come.
Take off jewelry when swimming or doing other physical activities.
Put on jewelry after applying lotion, hair spray, perfume or other chemicals.
For more jewelry care info, please visit our jewelry education page.
Have Questions?
Have Questions?
If you have any questions about our products or service, please contact us, call us 1-888-925-7569, online chat is also available.
Our friendly customer service agents will be glad to help. Our business hours are Monday to Saturday (9am - 5pm ET). Sunday (Closed).
You might want to check out our FAQ page to see if your question has already been answered.
