Solitaire 2.1ct Emerald Cut CZ Ring Set in Sterling Silver
Solitaire 2.1ct Emerald Cut CZ Ring Set in Sterling Silver
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Description
- Metal: Sterling silver, rhodium plated, stamped 925, nickel free.
- Stone: Set with premium quality 2.1 carat (8.5mm x 6.5mm) emerald cut cubic zirconia in 4-prong setting.
- Measurement: Ring measures 5.8mm in height. Bands measure 4.75mm in total width.
- Style No: VR101-09
This 2 piece solitaire ring set is the modern interpretation of simple luxury with its scintillating emerald cut center stone and minimalist bands.
The emerald cut is high in quality, yet simple in taste. Often showcased on the red carpet, it looks flawless and posh from every angle. If you like sophisticated styles, emerald cut styles are perfect for you.
Product Details & Materials
Product Details & Materials
Jewelry Information
| Style Number | VR101-09 |
|---|---|
| Metal | 925 sterling silver |
| Plating | rhodium plated |
| Finish | polished |
| Nickel Free | Yes |
| Ring Band Width | 4.75mm |
| Jewelry Weight | 4.3 Grams |
cubic zirconia Information
| Stone Cut | emerald cut |
|---|---|
| Stone Size | 8.5mm x 6.5mm |
| Stone Color | clear Color |
| Stone Setting | 4-prong |
| Stone Quantity | 1 Stone |
| Stone Weight | 2.1 ct.tw |
* All cubic zirconia stone weights are approximate and listed as diamond equivalent weight in carats.
Jewelry Care Tips
Jewelry Care Tips
Caring for your jewelry will ensure that it will last for years to come.
Take off jewelry when swimming or doing other physical activities.
Put on jewelry after applying lotion, hair spray, perfume or other chemicals.
For more jewelry care info, please visit our jewelry education page.
Have Questions?
Have Questions?
If you have any questions about our products or service, please contact us, call us 1-888-925-7569, online chat is also available.
Our friendly customer service agents will be glad to help. Our business hours are Monday to Saturday (9am - 5pm ET). Sunday (Closed).
You might want to check out our FAQ page to see if your question has already been answered.
