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Style# r1840-01

2-Stone Art Deco CZ Ring in Sterling Silver

2-Stone Art Deco CZ Ring in Sterling Silver

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  • 5% off on order over $500. No promo code needed.
  • Metal: Sterling silver, rhodium plated, stamped 925, nickel free.
  • Stone: Set with premium quality 2.32 carat total pear, round and tapered baguette cubic zirconia in bar and prong setting.
  • Measurement: Ring measures 4.6mm in height. Band measures 2mm in width.
  • Style No: R1840-01

This 2-stone art deco ring boats an unique and intricate design, ideal for those who treasure one of a kind styles.

An iconic jewelry cut for centuries, the pear cut, also known as teardrop shape, dazzles with multi-faceted brilliance in an elegant silhouette. Worn by celebrities like Elizabeth Taylor and Paris Hilton, this cut is perfect for those who love over-the-top glamour.

Product Details & Materials

Jewelry Information

Style NumberR1840-01
Metal925 sterling silver
Platingrhodium plated
Finishpolished
Nickel FreeYes
Ring Band Width2mm
Jewelry Weight2.99 Grams

cubic zirconia Information

Stone Cutpear cuttapered baguette cutround cut
Stone Size8mm x 5mm5mm x 3mm x 2mm1mm
Stone Colorclear Colorclear Colorclear Color
Stone Setting3-prongbar4-prong
Stone Quantity2 Stones2 Stones44 Stones
Stone Weight1.6 ct.tw0.5 ct.tw0.22 ct.tw

* All cubic zirconia stone weights are approximate and listed as diamond equivalent weight in carats.

Jewelry Care & Tips

Caring for your jewelry will ensure that it will last for years to come.

Take off jewelry when swimming or doing other physical activities.

Put on jewelry after applying lotion, hair spray, perfume or other chemicals.

For more jewelry care info, please visit our jewelry education page.

Have Questions?

If you have any questions about our products or service, please contact us, online chat is also available.

Our friendly customer service agents will be glad to help. Our business hours are Monday to Saturday (9am - 5pm ET). Sunday (Closed).

You might want to check out our FAQ page to see if your question has already been answered.

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