Bar Art Deco CZ Ring in Sterling Silver
Bar Art Deco CZ Ring in Sterling Silver
Description
- Metal: Sterling silver, rhodium plated, stamped 925, nickel free.
- Stone: Set with premium quality 1.15 carat total baguette, princess and round cubic zirconia in pave and prong setting.
- Measurement: Ring measures 3.7mm in height. Band measures 2.2mm - 8mm in width.
- Style No: R1219-01
This art deco bar ring features vintage-inspired geometric patterns and alternating stone cuts for the most mesmerizing brilliance.
Product Details & Materials
Product Details & Materials
Jewelry Information
Style Number | R1219-01 |
---|---|
Metal | 925 sterling silver |
Plating | rhodium plated |
Finish | polished |
Nickel Free | Yes |
Ring Band Width | 2.2mm - 8mm |
Jewelry Weight | 3.5 Grams |
cubic zirconia Information
Stone Cut | princess cut | princess cut | baguette cut | round cut | round cut |
---|---|---|---|---|---|
Stone Size | 3.5mm | 1.5mm | 4mm x 1.5mm | 2mm | 1mm - 1.5mm |
Stone Color | clear Color | clear Color | clear Color | clear Color | clear Color |
Stone Setting | 4-prong | 4-prong | prong | pave | pave |
Stone Quantity | 1 Stone | 2 Stones | 4 Stones | 6 Stones | 24 Stones |
Stone Weight | 0.3 ct.tw | 0.03 ct.tw | 0.32 ct.tw | 0.18 ct.tw | 0.32 ct.tw |
* All cubic zirconia stone weights are approximate and listed as diamond equivalent weight in carats.
Jewelry Care Tips
Jewelry Care Tips
Caring for your jewelry will ensure that it will last for years to come.
Take off jewelry when swimming or doing other physical activities.
Put on jewelry after applying lotion, hair spray, perfume or other chemicals.
For more jewelry care info, please visit our jewelry education page.
Have Questions?
Have Questions?
If you have any questions about our products or service, please contact us, call us 1-888-925-7569, online chat is also available.
Our friendly customer service agents will be glad to help. Our business hours are Monday to Saturday (9am - 5pm ET). Sunday (Closed).
You might want to check out our FAQ page to see if your question has already been answered.







