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Style# vr292-02

Solitaire 1.2ct Princess CZ Ring Set in Sterling Silver

Solitaire 1.2ct Princess CZ Ring Set in Sterling Silver

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  • 5% off on order over $500. No promo code needed.
  • Metal: Sterling silver, rhodium plated, stamped 925, nickel free.
  • Stone: Main stone features premium quality 1.2 carat (6mm) princess cubic zirconia in 4-prong setting. Accented with 1.68 ct. tw. round CZ in pave setting.
  • Measurement: Bands measure 7mm in total width.
  • Style No: VR292-02

This 3-piece solitaire ring set is embellished with a deep hue and high setting for a striking impression.

The perfect combination of shine, sweetness and style, a princess cut style is ideal for someone girly and lively.

Tips!
This ring's band width is wide, so we suggest you choose a ring size 1/2 or 1 size larger than your standard ring size to make sure the ring will fit comfortably.

Product Details & Materials

Jewelry Information

Style NumberVR292-02
Metal925 sterling silver
Platingrhodium plated
Finishpolished
Nickel FreeYes
Ring Band Width7mm
Jewelry Weight6.4 Grams

cubic zirconia Information

Stone Cutprincess cutround cutround cut
Stone Size6mm2mm2mm
Stone Colorclear Colorclear Colorsapphire Color
Stone Setting4-prongpavepave
Stone Quantity1 Stone28 Stones28 Stones
Stone Weight1.2 ct.tw0.84 ct.tw0.84 ct.tw

* All cubic zirconia stone weights are approximate and listed as diamond equivalent weight in carats.

Jewelry Care & Tips

Caring for your jewelry will ensure that it will last for years to come.

Take off jewelry when swimming or doing other physical activities.

Put on jewelry after applying lotion, hair spray, perfume or other chemicals.

For more jewelry care info, please visit our jewelry education page.

Have Questions?

If you have any questions about our products or service, please contact us, online chat is also available.

Our friendly customer service agents will be glad to help. Our business hours are Monday to Saturday (9am - 5pm ET). Sunday (Closed).

You might want to check out our FAQ page to see if your question has already been answered.

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